0=5x^2-26x+32

Solution for 0=5x^2-26x+32 equation:

0=5x^2-26x+32

We move all terms to the left:

0-(5x^2-26x+32)=0

We add all the numbers together, and all the variables

-(5x^2-26x+32)=0

We get rid of parentheses

-5x^2+26x-32=0

a = -5; b = 26; c = -32;
Δ = b2-4ac
Δ = 262-4·(-5)·(-32)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-6}{2*-5}=\frac{-32}{-10}
=3+1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+6}{2*-5}=\frac{-20}{-10}
=+2
$